Friday, January 11, 2013

Aim: How do we add and subtract algebraic fractions with a common denominator?



Notice Midterm  Test  Tues January 15


  • Topics to include:

  • - simplifying /reduce algebraic fractions
  • - mulitplying algebraic fractions 
  • - Dividing algebraic fractions
  • - combining algebraic fractions
  • - solving equations
  • scientific notation 
  • solving literal equations
  • combining polnomials
Homework:
Complete handout side # 1 and 2 all problems.


Lesson Review:
Remember that a rational expression is a fraction. The objective in this lesson is to combine t two algebraic fractions and reduce the answer to the most simplifed form.These expressions can be monimials or polynomials in factored or unfactored form.

THE 4 STEP PROCEDURE IS AS FOLLOWS:
1. Check for common denominator
2. Combine the numerators over the common denominator of only one fraction
3. Cancel terms or factor if possible
4. Reduce and cancel like terms.
Click below for lesson summary:
http://www.regentsprep.org/Regents/math/fractions/addsubt.htm
Practice Exercise:
http://www.regentsprep.org/Regents/math/fractions/Paddsubt1.htm

1 comment:

Anonymous said...

TREASAN MARTINDALE
PD:10
ROOM: 244
December.13.2008

HI MR. NAPOLI!!!!!

Homework Side #2 All problems
(I'm sorry I couldn't put the line between the fractions)

1) 7 - 3 = 4
2d 2d 2d

ANSWER: 4
2d ::4 over 2d

2)4 - 1 = 1
3a2 3a2 a2

ANSWER: 1
a2 :: 1 over a squared

3) 4k _ k = 1
3k2 3k2 k

ANSWER 1
K:: 1 OVER K

4) 5m + 5m = 2
4m2 4m2 M

ANSWER: 2
M :: 2 over M

5) 2x + x = 3x
3x+1 3x+1 3x+1

ANSWER: 3X
3X+1 :: 3x over 3x+1
**HINT** HINT***: You DON'T cancel the 3x, because they are connected by a +(Plus) sign

6) 4x+12 + 8x+4 = 3x+4
16x 16x 4x

ANSWER: 3x+4
4x :: 3x+4 over 4x

7)2x _ 14 = 2
x-7 x-7

ANSWER:2

8)2d2+3 + 2d2-1 = 1
4d2+2 4d2+2

ANSWER:1

9) 12a-15 _ 9a-6 = a-3
12a 12a 4a

ANSWER: a-3
4a :: a minus 3 over 4a

10)2y+1 _ y+2 + 1
y-1 y-1

ANSWER:1

11) 3n-2 _ n-6 = 2n+4
n+4 n+4 n+4

ANSWER: 2n+4
n+4 :: 2n + 4 Over n+4

12) 6x-5 _ 5x-6 = 1
x2-1 x2-1 (x-1)

ANSWER: 1
(x-1) :: 1 over x-1