Tuesday, October 18, 2011

Aim: How do we solve EVEN and ODD consecutive integer problems.








Homework: . Consecutive even and odd integer problems, all problems both sides. )

Lesson review:
For consecutive odd or even integers, also always start with a Let Statement and increment by 2:

ExampleLet:1st # = x
2nd # = x+2
3rd # = x+4
4th # = x+6
Then translate a verbal problem into an algebraic equation and solve

1 comment:

T said...

Theresa Kong.


friday's handout side one

1] 2x+1=123
2x=122
x=61
x= 61; x+1=62

2] 2x+1=-97
2x=-98
x=-49
x=-49; x+1=-48

3] 3x+3=171
3x=168
x=56
x=56; x+1=57; x+2=58

4] 3x+3=-54
3x=-57
x=-19
x=-19; x+1=-18; x+2=-17

5] 2x+2=54
2x=52
x=26
x=26; x+2=28

6] 2x+2=-38
2x=-40
x=-20
x=-20; x+2=-18

7] 3x+6=84
3x=78
x=26
x=26; x+2= 28; x+4=30

8] 3x+6=-48
3x=-54
x=-18
x=-18; x+2=-16; x+4=-14

9] 2x+2=128
2x=126
x=63
x=63; x+2=65

10] 2x+2=-36
2x=-38
x=-19
x=-19; x+2=-17

11] 3x+6=75
3x=69
x=23
x=23; x+2=25; x+4=27

12] 3x+6=-45
3x=-51
x=-17
x=-17; x+2= -15; x+4=-13

13] 7x+x+4=70
2x+4=70
2x=66
x=33
x=33; x+2= 35; x+4=37

14] 3x=x+16
2x=16
x=8
x=8; x+1=9; x+2=10

15] 2x+2=3(x+4)-31
2x+2=3x-19
2=x-19
x=21
x=21; x+2=23; x+4=25

16] x+3(x+2)=2(x+4)+38
x+3x+6=2x+8+38
4x+6=2x+46
4x+6=2x+46
4x+6=46
4x=40
x=10
x=10; x+2=12; x+4=14


side two

1] 4x+12=112
4x=100
x=25
x=25; x+2=27; x+4=29; x+6=31

2] 2x+1=x+2+24
2x+1=x+26
x=25
x=25; x+1=26; x+2=27

3] 2x+2=3(x+4)-27
2x+2=3x+12-27
2x=3x-15
x=15
x=15; x+2=17; x+4=19

4] 4(x+1)=3x+23
4x+4=3x+23
x+4=23
x=19
x=19; x+1=20

5] 3x+6=x+6+18
3x+6=x+24
2x+6=24
2x=18
x=9
x=9; x+2=11; x+4=13; x+6=15

6] (x+4)-2(x+2)=x-10
x+4-2x+4=x-10
-x+8=x-10
8=2x-10
18=2x
x=9
x=9; x+2=11; x+4=11; x+6=13

7] 2x+2=3(x+4)+10
2x+2=3x+12+10
2x+2=x+22
2=x+22
-20=x
x=-20; x+2=-18; x+4=-16

8] 2(2x+6)=3x+43
4x+12=3x+43
x+12=43
x=31
x=31; x+2=33; x+4= 35

9] 3x+6=2x+12+5
3x+6=2x+17
x+6=17
x=11
x=11; x+2=13; x+4=15; x+6=17

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