Thursday, September 27, 2012
Aim: How do you solve two step equations of the form ax + b = c and a/x + b = c
Homework: Textbook pg. 122 #'s 5 - 12, 18, 19, 20, 25
Lesson Review:
http://www.regentsprep.org/Regents/math/ALGEBRA/AE2/LSolvEq.htm
Practice Exercise:
http://www.regentsprep.org/Regents/math/ALGEBRA/AE2/PSolvEq.htm
Video Lesson: TBS if available
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3 comments:
Michelle Chue P9
Solving Linear equations 1
1)minus 3 to both sides 6x=12 divide 6 to both sides x=2
2) Minus 1 to both sides 2x=-10 divide 2 to both sides x=-5
3)add 5 to both sides 3x=12 divide 3 to both sides x=4
4)add 2 to both sides 5x=8 divide by 5 x=8/5
5)minus 3 from both sides -4x=-12 divide both sides by -4 x=3
6)add 5 to both sides -2x=1 divide both sides by -2 x=-0.5
7)multiply both sides by 2 -x=-14 divide both sides by -1 x=14
8)add 1 to both sides 3x=3 divide both sides by 3 x=1
9)add 5 to both sides 4x=12 divide both sides by 4 x=3
10)minus 4 to both sides 3x/2=5 multiply both sides by 2 3x=10
divide both sides by 3 x=3.33...
Solving Linear equations 2
1)subtract 2 divide by 5 x=2
2)subtract 3 divide by 4 x=-5
3)add 3 divide by 2 x=4
4)add 7 divide by 3 x+1.66...
5)subtract 5 multiply by 2 divide by -3 x=6
6)add 3 divide by -2 x=2
7)add 5 multiply by 2 divide by -1 x=-2
8)add 2 divide by 5 x= 1
9)add 3 divide by 6 x= 1.66..
10)minus 1 multiply by 3 divide 2 x=6
HII MR. NAPOLI :DDDDDDD
this is Theresa Kong.
& here's the answer for tonight's homework,,,,
1) minus two on both sides, then divided by 5 and i get 2
2) minus three [i get -21] then divided by four and i get negative five and one fourth
3) plus three on both sides[i get 8] then divided by two and i get 4
4) plus seven on both sides [i get 5] then divided by three and i get one and two-thirds
5) minus five on both sides [i get -9 = - three X over two] then -9 times -2 = 18, finally 18 divided by three is 6
6) plus three on both sides [-2x = -4] and -4/-2 is 2
7) plus five on both sides [2 = - x/2] then 2*-2 = -4
8) plus two on both sides [5x = 5] then 5/5 = 1
9) plus three on both sides [6x = 10] and finally x equals one and four over six (OR one and two over three as a mixed number)
10) minus one on both sides [2x/3 = 4] then [2x = 12] and x finally equals 6
Dan Yang Zhang
HW 9/24/08 text book pg 132
4. Plus 2x on both sides, then divided by 11 on both sides. x=4
6. Minus y on both sides, then minus 3y on both sides, and then divided by 3 on both sides. y=-10
10. Plus 2y on both sides, then divided by 10 on both sides. y=9.
14. Minus 2c on both sides, then divided 3 on both sides. c=-27
16. Minus 0.5m on both sides, then divided by 0.6 on both sides. m=-50
18. Minus 3r on both sides, then minus 10 on both sides, and the divided by 4 on both sides. r=10
24. Plus 4c on both sides, then minus 20 on both sides, and the divided by 5 on both sides. c=7
26. Minus 7y on both sides, then minus 29 on both sides, and the divided by 2 on both sides. y=-17.
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